JAVASCRIPT , CSS , PHP 判斷瀏覽器

JavaScript , CSS , PHP 判斷瀏覽器之作法，如下：





JavaScript

<script type="text/javascript">
    var isIE = navigator.userAgent.search("MSIE") > -1;
    var isIE7 = navigator.userAgent.search("MSIE 7") > -1;
    var isFirefox = navigator.userAgent.search("Firefox") > -1;
    var isOpera = navigator.userAgent.search("Opera") > -1;
    var isSafari = navigator.userAgent.search("Safari") > -1;//Google瀏覽器是用這核心
    if (isIE7) {
        alert('isIE7');
    }
    if (isIE) {
        alert('isIE');
    }
    if (isFirefox) {
        alert('isFirefox');
    }
    if (isOpera) {
        alert('isOpera');
    }
    if (isSafari) {
        alert('isSafari or Chrome');
    }
</script>

CSS

.classname{
 
background:blue; /*Firefox等非IE瀏覽器背景變藍色*/
background:red \9; /*IE8 背景變紅色*/
*background:black; /*IE7 背景變黑色*/
_background:orange; /*IE6 背景變橘色*/
 
}

PHP

//偵測瀏覽器
$agent = $_SERVER['HTTP_USER_AGENT'];
if(strpos($agent,"MSIE 8.0"))
  echo "Internet Explorer 8.0";
else if(strpos($agent,"MSIE 7.0"))
  echo "Internet Explorer 7.0";
else if(strpos($agent,"MSIE 6.0"))
  echo "Internet Explorer 6.0";
else if(strpos($agent,"Firefox/3"))
  echo "Firefox 3";
else if(strpos($agent,"Firefox/2"))
  echo "Firefox 2";
else if(strpos($agent,"Chrome"))
  echo "Google Chrome";
else if(strpos($agent,"Safari"))
  echo "Safari";
else if(strpos($agent,"Opera"))
  echo "Opera";
else
  echo $agent;

文章參考：http://ithelp.ithome.com.tw/question/10095184